Tour de Suisse 1989
Stage 6
Baden → Heitersberg
Stage Data
Stage 6 of the 1989 Tour de Suisse, held on June 18, 1989, covered 7.5 km from Baden to Heitersberg. The stage was completed at an average speed of 37.4 km/h, which was 2.0 km/h slower than the edition average of 39.4 km/h. At 7.5 km, this was one of the shortest stages in the edition. This was an individual time trial, where riders raced alone against the clock.
Baden → Heitersberg
Stage 5B (ITT) | Baden - Heitersberg
Avg Speed
37.4 km/h
Win Type
Time trial
Won How
Time trial
Startlist Quality
604
Nearby Stages
Lausanne → Liestal
199 km
Liestal → Bad Zurzach
167 km
Bad Zurzach → Baden
78 km
Baden → Arosa
203 km
Arosa → Bellinzona
209 km
Bellinzona → Zermatt
200 km
Frequently Asked Questions
How long was Stage 6 of the 1989 Tour de Suisse?
Stage 6 covered 7.5 km from Baden to Heitersberg.
What was the route of Stage 6 in the 1989 Tour de Suisse?
Stage 6 ran from Baden to Heitersberg, a distance of 7.5 km.
What was the average speed of Stage 6 in the 1989 Tour de Suisse?
The average winning speed for Stage 6 was 37.4 km/h.