Tour de Suisse 1989
Stage 5
Bad Zurzach → Baden
Stage Data
Stage 5 of the 1989 Tour de Suisse, held on June 18, 1989, covered 78.0 km from Bad Zurzach to Baden. The stage was completed at an average speed of 39.1 km/h. At 78.0 km, this was one of the shortest stages in the edition.
Road race78.0 km18 Jun 1989
Bad Zurzach → Baden
Stage 5A | Bad Zurzach - Baden
Avg Speed
39.1 km/h
Startlist Quality
604
Nearby Stages
2
Bern → Lausanne
198 km
3
Lausanne → Liestal
199 km
4
Liestal → Bad Zurzach
167 km
6
Baden → Heitersberg
8 km
7
Baden → Arosa
203 km
8
Arosa → Bellinzona
209 km
Frequently Asked Questions
How long was Stage 5 of the 1989 Tour de Suisse?
Stage 5 covered 78.0 km from Bad Zurzach to Baden.
What was the route of Stage 5 in the 1989 Tour de Suisse?
Stage 5 ran from Bad Zurzach to Baden, a distance of 78.0 km.
What was the average speed of Stage 5 in the 1989 Tour de Suisse?
The average winning speed for Stage 5 was 39.1 km/h.