Tour de Suisse 1969
Stage 10
Zurzach → Zurzach
Stage Data
Stage 10 of the 1969 Tour de Suisse, held on June 20, 1969, covered 44.0 km from Zurzach to Zurzach. The stage was completed at an average speed of 41.6 km/h, which was 4.5 km/h faster than the edition average of 37.1 km/h, ranking as the 2nd fastest stage of the race. At 44.0 km, this was one of the shortest stages in the edition. This was an individual time trial, where riders raced alone against the clock.
Zurzach → Zurzach
Stage 9a (ITT) | Zurzach - Zurzach
Avg Speed
41.6 km/h
Win Type
Time trial
Won How
Time trial
Startlist Quality
700
Nearby Stages
Crans-Montana → Lugano
225 km
Lugano → Jakobshorn
197 km
Davos → Wohlen
175 km
Wohlen → Zurzach
88 km
Frequently Asked Questions
How long was Stage 10 of the 1969 Tour de Suisse?
Stage 10 covered 44.0 km from Zurzach to Zurzach.
What was the route of Stage 10 in the 1969 Tour de Suisse?
Stage 10 ran from Zurzach to Zurzach, a distance of 44.0 km.
What was the average speed of Stage 10 in the 1969 Tour de Suisse?
The average winning speed for Stage 10 was 41.6 km/h.