Tour de France 1947
Stage 20
Saint-Brieuc → Caen
Race Report
Stage 20 of the 1947 Tour de France, held on July 18, 1947, covered 235.0 km from Saint-Brieuc to Caen. Maurice Diot won the stage. Classified as a hilly stage with a flat finish. The riders faced 2,427 meters of total elevation gain. The stage was completed at an average speed of 36.8 km/h, which was 4.5 km/h faster than the edition average of 32.3 km/h, ranking as the fastest stage of the race.
Saint-Brieuc → Caen
Stage 20 | Saint-Brieuc - Caen
Stage Winner
Maurice Diot
Yellow Jersey
Pierre Brambilla
Avg Speed
36.8 km/h
Elevation
2,427 m
Difficulty
53
Startlist Quality
575
Jersey Classifications
Yellow Jersey
Pierre Brambilla
Polka-Dot Jersey
Nan
Edition Difficulty Profile
Nearby Stages
Bordeaux → Les Sables
272 km
Eloi Tassin
Les Sables → Nantes
236 km
Pietro Tarchini
Vannes → Saint-Brieuc
139 km
Raymond Impanis
Caen → Paris
257 km
Brik Schotte
Frequently Asked Questions
Who won Stage 20 of the 1947 Tour de France?
Maurice Diot won Stage 20 of the 1947 Tour de France.
How long was Stage 20 of the 1947 Tour de France?
Stage 20 covered 235.0 km from Saint-Brieuc to Caen. The total elevation gain was 2,427 meters.
Who wore the yellow jersey after Stage 20 of the 1947 Tour de France?
Pierre Brambilla wore the yellow jersey (maillot jaune) after Stage 20 of the 1947 Tour de France.
What was the route of Stage 20 in the 1947 Tour de France?
Stage 20 ran from Saint-Brieuc to Caen, a distance of 235.0 km. It was classified as a hills flat finish stage.
What was the average speed of Stage 20 in the 1947 Tour de France?
The average winning speed for Stage 20 was 36.8 km/h. The stage profile was classified as hills flat finish.