Tour de France 1912 Stage 10

Tour de France 1912

Stage 10

Luchon → Bayonne

Stage Result

Stage 10 of the 1912 Tour de France, held on July 18, 1912, covered 326.0 km from Luchon to Bayonne. Louis Mottiat won the stage. Classified as a mountain stage with a flat finish after the final descent. The stage was completed at an average speed of 22.8 km/h, which was 5.2 km/h slower than the edition average of 27.9 km/h.

Road raceMountains flat finish326.0 km18 Jul 1912

Luchon → Bayonne

Stage 10 | Luchon - Bayonne

Stage Winner

Louis Mottiat

Avg Speed

22.8 km/h

Startlist Quality

1,061

Race Leader

ODIEL DEFRAEYE

Jersey Classifications

Race Leader

ODIEL DEFRAEYE

Nearby Stages

7

Nice → Marseille

334 km

Odiel Defraeye

8

Marseille → Perpignan

335 km

Vicenzo Borgarello

9

Perpignan → Luchon

289 km

Odiel Defraeye

11

Bayonne → La Rochelle

379 km

Jean Alavoine

12

La Rochelle → Brest

470 km

Louis Heusghem

13

Brest → Cherbourg-en-Cotentin

405 km

Jean Alavoine

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Frequently Asked Questions

Who won Stage 10 of the 1912 Tour de France?

Louis Mottiat won Stage 10 of the 1912 Tour de France.

How long was Stage 10 of the 1912 Tour de France?

Stage 10 covered 326.0 km from Luchon to Bayonne.

What was the route of Stage 10 in the 1912 Tour de France?

Stage 10 ran from Luchon to Bayonne, a distance of 326.0 km. It was classified as a mountains flat finish stage.

What was the average speed of Stage 10 in the 1912 Tour de France?

The average winning speed for Stage 10 was 22.8 km/h. The stage profile was classified as mountains flat finish.