Tour de France 1910

Stage 2

Roubaix → Metz

Stage Result

Stage 2 of the 1910 Tour de France, held on July 5, 1910, covered 398.0 km from Roubaix to Metz. François Faber won the stage. Classified as a flat stage suited for sprinters. The stage was completed at an average speed of 30.3 km/h. This was the 2nd longest stage of the edition at 398.0 km.

Road raceFlat398.0 km5 Jul 1910

Roubaix → Metz

Stage 2 | Roubaix - Metz

Stage Winner

François Faber

Avg Speed

30.3 km/h

Startlist Quality

775

Race Leader

FRANÇOIS FABER

Jersey Classifications

Race Leader

FRANÇOIS FABER

Nearby Stages

Paris → Roubaix

269 km

Charles Crupelandt

Metz → Belfort

259 km

Emile Georget

Belfort → Lyon

309 km

François Faber

Lyon → Grenoble

311 km

Octave Lapize

chevron_left Stage 1 Stage 3 arrow_forward

Frequently Asked Questions

Who won Stage 2 of the 1910 Tour de France?

François Faber won Stage 2 of the 1910 Tour de France.

How long was Stage 2 of the 1910 Tour de France?

Stage 2 covered 398.0 km from Roubaix to Metz.

What was the route of Stage 2 in the 1910 Tour de France?

Stage 2 ran from Roubaix to Metz, a distance of 398.0 km. It was classified as a flat stage.

What was the average speed of Stage 2 in the 1910 Tour de France?

The average winning speed for Stage 2 was 30.3 km/h. The stage profile was classified as flat.