Tour de France 1905

Stage 10

Rennes → Caen

Stage Result

Stage 10 of the 1905 Tour de France, held on July 28, 1905, covered 167.0 km from Rennes to Caen. Jean-Baptiste Dortignacq won the stage. Classified as a flat stage suited for sprinters. The stage was completed at an average speed of 25.5 km/h, which was 2.4 km/h slower than the edition average of 27.9 km/h. At 167.0 km, this was one of the shortest stages in the edition.

Road raceFlat167.0 km28 Jul 1905

Rennes → Caen

Stage 10 | Rennes - Caen

Stage Winner

Jean-Baptiste Dortignacq

Avg Speed

25.5 km/h

Startlist Quality

515

Race Leader

LOUIS TROUSSELIER

Jersey Classifications

Race Leader

LOUIS TROUSSELIER

Nearby Stages

Toulouse → Bordeaux

268 km

Louis Trousselier

Bordeaux → La Rochelle

257 km

Hippolyte Aucouturier

La Rochelle → Rennes

263 km

Louis Trousselier

Caen → Paris

253 km

Jean-Baptiste Dortignacq

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Frequently Asked Questions

Who won Stage 10 of the 1905 Tour de France?

Jean-Baptiste Dortignacq won Stage 10 of the 1905 Tour de France.

How long was Stage 10 of the 1905 Tour de France?

Stage 10 covered 167.0 km from Rennes to Caen.

What was the route of Stage 10 in the 1905 Tour de France?

Stage 10 ran from Rennes to Caen, a distance of 167.0 km. It was classified as a flat stage.

What was the average speed of Stage 10 in the 1905 Tour de France?

The average winning speed for Stage 10 was 25.5 km/h. The stage profile was classified as flat.